Abc conjecture

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The abc conjecture is a formula which holds for "almost all" triples of numbers with certain characteristics:

Let ε > 0 be fixed. Then for almost all triplets of co-prime integers a, b and c with a+b=c holds:

<math>rad(a b c)^{1+\epsilon} > c</math>

Here rad(a b c) is the "radical" of the product <math>a \times b \times c</math>, i.e., the product of all unique primes dividing <math>a \times b \times c</math> - or, in other words, the square-free-part.[1]

"Almost all triplets" means that there is only a finite number of triplets which violates the condition. Some observations:

  • ε can be chosen as small as you like - as long it is greater than zero.
  • the finite number of exceptions obviously becomes smaller, the bigger ε is chosen.
  • There are infinitely many triplets violating <math>rad(a b c) > c</math> - that's why <math>\epsilon = 0</math> isn't allowed.

Informally, one effect of this conjecture is that adding to co-prime numbers with many divisors will generally result in a sum which has only a few big prime factors.

An example of an exception to this rule for small ε is provided by Nature is as follows:[2]

  • a = 3
  • b = 125 = 53
  • c = 128 = 27

Then reg(abc) = reg(48000) = 3*5*2 = 30 and therefore

reg(48000)1+ε > 128 only if ε > .4265....

An asserted proof for the abc conjecture was posted by the prominent mathematician Shinichi Mochizuki on the internet in 2012.[3]

See also

References

  1. ↑ The square-free-part (sqp) of a number is defined as the biggest divisor of this number which itself is not divisible by the square of a prime number. This is equal to the product of the different prime-factors of this number
  2. ↑ http://www.nature.com/news/the-biggest-mystery-in-mathematics-shinichi-mochizuki-and-the-impenetrable-proof-1.18509
  3. ↑ http://www.nature.com/news/proof-claimed-for-deep-connection-between-primes-1.11378