Difference between revisions of "Quadratic formula"
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(It doesn't simplify anything. Factoring simplifies.) |
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| − | The '''quadratic formula''' | + | The '''quadratic formula''' can be used when simpler methods of solving a [[quadratic equation]] do not work. |
First, the quadratic equation must be reduced to this format: | First, the quadratic equation must be reduced to this format: | ||
Revision as of 20:31, October 10, 2010
The quadratic formula can be used when simpler methods of solving a quadratic equation do not work.
First, the quadratic equation must be reduced to this format:
- <math>ax^2+bx+c=0\!</math>
Then the coefficients a, b, and c can be substituted in the formula to find the solutions:
- <math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math>
You can prove the formula the following way:
- <math>ax^2+bx+c=0\!</math>
- <math>x^2+\frac{b}{a}x+\frac{c}{a}=0\!</math>
- <math>(x+\frac{b}{2a})^2-(\frac{b}{2a})^2+\frac{c}{a}=0\!</math>
- <math>(x+\frac{b}{2a})^2=(\frac{b}{2a})^2-\frac{c}{a}\!</math>
- <math>(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}\!</math>
- <math>x+\frac{b}{2a}=\frac{\pm \sqrt {b^2-4ac}}{2a}\!</math>
- <math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math>
This method of deriving the formula is done via completing the square.
You can assert that the formula is correct by substituting the formula in place of x in <math>ax^2+bx+c=0\!</math> and then gradually simplifying the rather complicated formula that results, step by step. Eventually, if all the steps are done correctly, it will simplify to 0.