Difference between revisions of "Diagonalizable"
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An operator ''T'' on a finite-dimensional vectorspace ''V'' is diagonalizeable if ''V'' has a basis of eigenvectors for ''T''. | An operator ''T'' on a finite-dimensional vectorspace ''V'' is diagonalizeable if ''V'' has a basis of eigenvectors for ''T''. | ||
| − | [[Category: Mathematics | + | [[Category:Mathematics]] |
Revision as of 23:33, July 4, 2008
An operator T on a finite-dimensional vectorspace V is diagonalizeable if V has a basis of eigenvectors for T.