Difference between revisions of "Quadratic formula"
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:<math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math> | :<math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math> | ||
| − | You can prove that the formula is correct by substituting the formula in place of '''x''' in <math>ax^2+bx+c=0\!</math> and then gradually simplifying the rather complicated formula that results, step by step. Eventually, if all the steps are done correctly, it will simplify to 0. | + | You can prove the formula the following way: |
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| + | :<math>ax^2+bx+c=0\!</math> | ||
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| + | :<math>x^2+\frac{b}{a}x+\frac{c}{a}=0\!</math> | ||
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| + | :<math>(x+\frac{b}{2a})^2-(\frac{b}{2a})^2+\frac{c}{a}=0\!</math> | ||
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| + | :<math>(x+\frac{b}{2a})^2=(\frac{b}{2a})^2-\frac{c}{a}\!</math> | ||
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| + | :<math>(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}\!</math> | ||
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| + | :<math>x+\frac{b}{2a}=\frac{\pm \sqrt {b^2-4ac}}{2a}\!</math> | ||
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| + | :<math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math> | ||
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| + | This method of deriving the formula is done via the method of [[completing the square]]. | ||
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| + | You can assert that the formula is correct by substituting the formula in place of '''x''' in <math>ax^2+bx+c=0\!</math> and then gradually simplifying the rather complicated formula that results, step by step. Eventually, if all the steps are done correctly, it will simplify to 0. | ||
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[[Category:Mathematics]] | [[Category:Mathematics]] | ||
Revision as of 18:50, July 3, 2008
- It has been proposed that this page, :Quadratic formula, be titled, "quadratic formula".
The quadratic formula is used to simplify the process of solving a quadratic equation.
First, the quadratic equation must be reduced to this format:
- <math>ax^2+bx+c=0\!</math>
Then the coefficients a, b, and c can be substituted in the formula to find the solutions:
- <math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math>
You can prove the formula the following way:
- <math>ax^2+bx+c=0\!</math>
- <math>x^2+\frac{b}{a}x+\frac{c}{a}=0\!</math>
- <math>(x+\frac{b}{2a})^2-(\frac{b}{2a})^2+\frac{c}{a}=0\!</math>
- <math>(x+\frac{b}{2a})^2=(\frac{b}{2a})^2-\frac{c}{a}\!</math>
- <math>(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}\!</math>
- <math>x+\frac{b}{2a}=\frac{\pm \sqrt {b^2-4ac}}{2a}\!</math>
- <math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math>
This method of deriving the formula is done via the method of completing the square.
You can assert that the formula is correct by substituting the formula in place of x in <math>ax^2+bx+c=0\!</math> and then gradually simplifying the rather complicated formula that results, step by step. Eventually, if all the steps are done correctly, it will simplify to 0.