Difference between revisions of "Completing the square"
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It is first taught using equations with "friendly" numbers in place of ''a'', ''b'', and ''c'' to get the student used to the process. | It is first taught using equations with "friendly" numbers in place of ''a'', ''b'', and ''c'' to get the student used to the process. | ||
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| + | :What one does is add and multiply by various carefully chosen constants to create an equation of the form: | ||
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| + | :<math>d^2x^2 + 2dex + e^2 = f</math> where ''d'', ''e'' and ''f'' are constants expressed in ''a'', ''b'', and ''c''. | ||
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| + | :This resolves to: | ||
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| + | ::<math>(dx+e)^2 = f</math> (grouping) | ||
| + | ::<math>dx + e = \pm \sqrt{f}</math> (take square root) | ||
| + | ::<math>dx = -e \pm \sqrt{f}</math> (subtract e) | ||
| + | ::<math>x = \frac{-e \pm \sqrt{f}}{d}</math> (divide by e) | ||
By then applying the process to the general equation, we can derive the [[quadratic formula]]: | By then applying the process to the general equation, we can derive the [[quadratic formula]]: | ||
| − | <math>ax^2 + bx + c = 0</math> (given) | + | :<math>ax^2 + bx + c = 0</math> (given) |
| − | <math>4a^2x^2 + 4abx + 4ac = 0</math> (multiply by 4a) | + | :<math>4a^2x^2 + 4abx + 4ac = 0</math> (multiply by 4a) |
| − | <math>4a^2x^2 + 4abx = -4ac</math> (subtract 4ac) | + | :<math>4a^2x^2 + 4abx = -4ac</math> (subtract 4ac) |
| − | <math>4a^2x^2 + 4abx + b^2 = -4ac + b^2</math> (add b^2) | + | :<math>4a^2x^2 + 4abx + b^2 = -4ac + b^2</math> (add b^2) |
| − | <math>(2ax + b)^2 = b^2 - 4ac</math> (group each side) | + | :<math>(2ax + b)^2 = b^2 - 4ac</math> (group each side) |
| − | <math>2ax + b = \pm \sqrt{b^2 - 4ac}</math> (take sqaure root, allow for both roots) | + | :<math>2ax + b = \pm \sqrt{b^2 - 4ac}</math> (take sqaure root, allow for both roots) |
| − | <math>2ax = -b \pm \sqrt{b^2 - 4ac}</math> (subtract b) | + | :<math>2ax = -b \pm \sqrt{b^2 - 4ac}</math> (subtract b) |
| − | <math>x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}</math> (divide by 2a) | + | :<math>x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}</math> (divide by 2a) |
We can now determine the real or imaginary roots of any quadratic equation by simply inserting ''a'', ''b'', and ''c'' into the formula. | We can now determine the real or imaginary roots of any quadratic equation by simply inserting ''a'', ''b'', and ''c'' into the formula. | ||
Revision as of 19:19, April 24, 2007
Completing the square is a method for solving for the roots of the general quadratic equation:
, where
It is first taught using equations with "friendly" numbers in place of a, b, and c to get the student used to the process.
- What one does is add and multiply by various carefully chosen constants to create an equation of the form:
- where d, e and f are constants expressed in a, b, and c.
- This resolves to:
- (grouping)
- (take square root)
- (subtract e)
- (divide by e)
By then applying the process to the general equation, we can derive the quadratic formula:
- (given)
- (multiply by 4a)
- (subtract 4ac)
- (add b^2)
- (group each side)
- (take sqaure root, allow for both roots)
- (subtract b)
- (divide by 2a)
We can now determine the real or imaginary roots of any quadratic equation by simply inserting a, b, and c into the formula.