Difference between revisions of "Quadratic formula"

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:<math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math>
 
:<math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math>
  
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This method of deriving the formula is done via the method of [[completing the square]].
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This method of deriving the formula is done via [[completing the square]].
  
 
You can assert that the formula is correct by substituting the formula in place of '''x''' in <math>ax^2+bx+c=0\!</math> and then gradually simplifying the rather complicated formula that results, step by step.  Eventually, if all the steps are done correctly, it will simplify to 0.   
 
You can assert that the formula is correct by substituting the formula in place of '''x''' in <math>ax^2+bx+c=0\!</math> and then gradually simplifying the rather complicated formula that results, step by step.  Eventually, if all the steps are done correctly, it will simplify to 0.   

Revision as of 18:52, July 3, 2008

  • It has been proposed that this page, :Quadratic formula, be titled, "quadratic formula".

The quadratic formula is used to simplify the process of solving a quadratic equation.

First, the quadratic equation must be reduced to this format:

<math>ax^2+bx+c=0\!</math>

Then the coefficients a, b, and c can be substituted in the formula to find the solutions:

<math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math>

You can prove the formula the following way:

<math>ax^2+bx+c=0\!</math>
<math>x^2+\frac{b}{a}x+\frac{c}{a}=0\!</math>
<math>(x+\frac{b}{2a})^2-(\frac{b}{2a})^2+\frac{c}{a}=0\!</math>
<math>(x+\frac{b}{2a})^2=(\frac{b}{2a})^2-\frac{c}{a}\!</math>
<math>(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}\!</math>
<math>x+\frac{b}{2a}=\frac{\pm \sqrt {b^2-4ac}}{2a}\!</math>
<math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math>

This method of deriving the formula is done via completing the square.

You can assert that the formula is correct by substituting the formula in place of x in <math>ax^2+bx+c=0\!</math> and then gradually simplifying the rather complicated formula that results, step by step. Eventually, if all the steps are done correctly, it will simplify to 0.