Difference between revisions of "Quadratic formula"

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(move according to MoS; no need for "The" in title)
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:<math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math>
 
:<math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math>
  
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You can prove that the formula is correct by substituting the formula in place of '''x''' in <math>ax^2+bx+c=0\!</math> and then gradually simplifying the rather complicated formula that results, step by step.  Eventually, if all the steps are done correctly, it will simplify to 0.   
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You can prove the formula the following way:
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:<math>ax^2+bx+c=0\!</math>
 +
 
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:<math>x^2+\frac{b}{a}x+\frac{c}{a}=0\!</math>
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:<math>(x+\frac{b}{2a})^2-(\frac{b}{2a})^2+\frac{c}{a}=0\!</math>
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:<math>(x+\frac{b}{2a})^2=(\frac{b}{2a})^2-\frac{c}{a}\!</math>
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:<math>(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}\!</math>
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:<math>x+\frac{b}{2a}=\frac{\pm \sqrt {b^2-4ac}}{2a}\!</math>
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 +
:<math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math>
 +
 
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This method of deriving the formula is done via the method of [[completing the square]].
 +
 
 +
You can assert that the formula is correct by substituting the formula in place of '''x''' in <math>ax^2+bx+c=0\!</math> and then gradually simplifying the rather complicated formula that results, step by step.  Eventually, if all the steps are done correctly, it will simplify to 0.   
 +
 
  
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Derivation of the formula is usually done via the method of [[completing the square]].
 
  
 
[[Category:Mathematics]]
 
[[Category:Mathematics]]

Revision as of 18:50, July 3, 2008

  • It has been proposed that this page, :Quadratic formula, be titled, "quadratic formula".

The quadratic formula is used to simplify the process of solving a quadratic equation.

First, the quadratic equation must be reduced to this format:

<math>ax^2+bx+c=0\!</math>

Then the coefficients a, b, and c can be substituted in the formula to find the solutions:

<math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math>

You can prove the formula the following way:

<math>ax^2+bx+c=0\!</math>
<math>x^2+\frac{b}{a}x+\frac{c}{a}=0\!</math>
<math>(x+\frac{b}{2a})^2-(\frac{b}{2a})^2+\frac{c}{a}=0\!</math>
<math>(x+\frac{b}{2a})^2=(\frac{b}{2a})^2-\frac{c}{a}\!</math>
<math>(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}\!</math>
<math>x+\frac{b}{2a}=\frac{\pm \sqrt {b^2-4ac}}{2a}\!</math>
<math>x = \frac{-b \pm \sqrt {b^2-4ac}}{2a}</math>

This method of deriving the formula is done via the method of completing the square.

You can assert that the formula is correct by substituting the formula in place of x in <math>ax^2+bx+c=0\!</math> and then gradually simplifying the rather complicated formula that results, step by step. Eventually, if all the steps are done correctly, it will simplify to 0.