Difference between revisions of "Talk:Conservapedia insights"
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At least both insights are equally valid. --[[User:AugustO|AugustO]] ([[User talk:AugustO|talk]]) 13:01, July 25, 2021 (EDT) | At least both insights are equally valid. --[[User:AugustO|AugustO]] ([[User talk:AugustO|talk]]) 13:01, July 25, 2021 (EDT) | ||
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| + | ===Proof that π does not contain π:=== | ||
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| + | 1) Let π be represented by the sequence of digits x<sub>0</sub>.x<sub>1</sub>=1, x<sub>2</sub>x<sub>3</sub>x<sub>4</sub>x<sub>5</sub>...... | ||
| + | Therefore x<sub>0</sub> = 3, x<sub>1</sub>, x<sub>2</sub>=4, x<sub>1000</sub>=9, and so on. | ||
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| + | 2) Assume that π contains π: Then there is an index <i>n</i> such that x<sub>0</sub> = x<sub>n</sub> = 3, | ||
| + | x<sub>1</sub> = x<sub>n+1</sub> = 1, x<sub>1000</sub> = x<sub>1000+n</sub> = 9, or in general x<sub>k</sub> = x<sub>n + k </sub> for all natural numbers k. | ||
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| + | 3) But then, π's representation is periodic: x<sub>0</sub> = x<sub>n</sub> = x<sub>2n</sub> = x<sub>3n</sub> = x<sub>w n</sub> for all natural numbers <i>w</i>. | ||
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| + | 4) Every number with a periodic representation is a rational number. In this case, we could present π as | ||
| + | x<sub>0</sub>x<sub>1</sub>x<sub>2</sub>x<sub>3</sub>...x<sub>n-1</sub> / (10<sup>n-1</sup> -1) | ||
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| + | 5) It is well know that π is not a rational number, so we have a contradiction. Ergo, π cannot contain itself. | ||
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| + | --[[User:AugustO|AugustO]] ([[User talk:AugustO|talk]]) 13:18, July 25, 2021 (EDT) | ||
Revision as of 17:18, July 25, 2021
I'm not sure which is funnier - that The Scotsman thought the Harvard student's column was serious or that Conservapedia is shouting at the rooftops about it. Read some of his other columns, like "Harvard Doesn't Hate Parties, They Just Hate Us" and the like, then reread the column's parts that are quoted. Then you can come back here and admit how embarrassed you are.--ThomasE 14:35, 11 May 2008 (EDT)
- The point is made with good humor - as in your second example about the lack of parties at Harvard. Or ... perhaps you think your example is trying to say that Harvard is a party school??? I guess you don't think much of political cartoons either.--Aschlafly 16:08, 11 May 2008 (EDT)
- Umm .... what? --CharlesN 16:22, 11 May 2008 (EDT)
- Hahah never mind, you're right, it does make a good point. Please leave it unchanged.--ThomasE 18:27, 11 May 2008 (EDT)
Two equally valid insights.
- Conservapedia observed that "Son of Man" is a liberal mistranslation to downplay the divinity of Jesus, and that a stronger, more precise translation would be "The Son as Man" or "The Son, a Man."
- Conservapedia observed that pi contains pi and every other number, despite liberal denial of the breadth and power of infinity.
At least both insights are equally valid. --AugustO (talk) 13:01, July 25, 2021 (EDT)
Proof that π does not contain π:
1) Let π be represented by the sequence of digits x0.x1=1, x2x3x4x5...... Therefore x0 = 3, x1, x2=4, x1000=9, and so on.
2) Assume that π contains π: Then there is an index n such that x0 = xn = 3, x1 = xn+1 = 1, x1000 = x1000+n = 9, or in general xk = xn + k for all natural numbers k.
3) But then, π's representation is periodic: x0 = xn = x2n = x3n = xw n for all natural numbers w.
4) Every number with a periodic representation is a rational number. In this case, we could present π as x0x1x2x3...xn-1 / (10n-1 -1)
5) It is well know that π is not a rational number, so we have a contradiction. Ergo, π cannot contain itself.