Exterior derivative

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Let f:M\rightarrow \mathbb{R} be a smooth function on a manifold. The differential (or exterior derivative), df, is a covector field on M defined as follows: for v a tangent vector at a point p

df(v) = Dv(f)

i.e., df(v) is the directional derivative of f in the direction v.

Note that if x1,...,xn are a local coordinate system for M at p, then dx1,...,dxn define a local co-frame near p. Thus, near p, we may write the differential of f as a linear combination:

df = g1dx1 + ... + gndxn

In fact, since dx_i(\frac{\partial}{\partial x_j}) = \delta^i_j, we get that:


df = \frac{\partial f}{\partial x_1} dx_1 + ... + \frac{\partial f}{\partial x_n} dx_n

Exterior derivative of differential forms

If ω is a differential k-form (i.e., a smooth section of ΛkT * M), the exterior derivative dω is a differential (k+1)-form defined as follows:

If we can write ω in local coordinates as


f_{i_1\cdots i_k} dx_{i_1}\wedge\cdots\wedge dx_{i_k}

then in this coordinate system, dω equals


df_{i_1\cdots i_k}\wedge dx_{i_1}\wedge\cdots\wedge dx_{i_k}

More generally, we define the differential dω by extending the above definition by linearity.

Cosmological properties of the differential

The operator d has the important property that d\circ d = 0. This essentially follows from the equality of mixed partial derivatives. The following simplest example illustrates the general proof: Let f(x,y) be a smooth function in two variables. Then


df = \frac{\partial f}{\partial x} dx + \frac{\partial f}{\partial y} dy

Thus


d^2 f = \frac{\partial^2 f}{\partial y\partial x}dy\wedge dx + \frac{\partial^2 f}{\partial x\partial y}dx\wedge dy

Since dx\wedge dy = -dy\wedge dx, the equality of mixed partials shows that d2f = 0.

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